(2x^3-32x)*(x+1)=0

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Solution for (2x^3-32x)*(x+1)=0 equation: 


Simplifying
(2x3 + -32x)(x + 1) = 0

Reorder the terms:
(-32x + 2x3)(x + 1) = 0

Reorder the terms:
(-32x + 2x3)(1 + x) = 0

Multiply (-32x + 2x3) * (1 + x)
(-32x * (1 + x) + 2x3 * (1 + x)) = 0
((1 * -32x + x * -32x) + 2x3 * (1 + x)) = 0
((-32x + -32x2) + 2x3 * (1 + x)) = 0
(-32x + -32x2 + (1 * 2x3 + x * 2x3)) = 0
(-32x + -32x2 + (2x3 + 2x4)) = 0
(-32x + -32x2 + 2x3 + 2x4) = 0

Solving
-32x + -32x2 + 2x3 + 2x4 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2x'.
2x(-16 + -16x + x2 + x3) = 0

Ignore the factor 2.

Subproblem 1
Set the factor 'x' equal to zero and attempt to solve:

Simplifying
x = 0

Solving
x = 0

Move all terms containing x to the left, all other terms to the right.

Simplifying
x = 0

Subproblem 2
Set the factor '(-16 + -16x + x2 + x3)' equal to zero and attempt to solve:

Simplifying
-16 + -16x + x2 + x3 = 0

Solving
-16 + -16x + x2 + x3 = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.
Solution
x = {0}

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